Determine the mass of lithium hydroxide produced when 0.38 grams – Delving into the determination of the mass of lithium hydroxide produced when 0.38 grams of a substance is provided, this exploration delves into the intricacies of molar mass, stoichiometry, and chemical reactions, providing a comprehensive understanding of this fundamental chemical process.
Lithium hydroxide, a versatile compound with diverse applications in industries ranging from pharmaceuticals to construction, serves as the focal point of this investigation. Through a series of precise calculations and insightful explanations, we will uncover the precise mass of lithium hydroxide produced under these specific conditions.
Determine the Mass of Lithium Hydroxide Produced
Lithium hydroxide (LiOH) is a versatile inorganic compound with applications in various industries, including the production of ceramics, batteries, and pharmaceuticals. In this article, we will determine the mass of lithium hydroxide produced when 0.38 grams of the compound is subjected to a specific chemical reaction.
Determining Molar Mass
Molar mass, expressed in grams per mole (g/mol), is the mass of one mole of a substance. To determine the mass of lithium hydroxide produced, we need to first calculate its molar mass.
The chemical formula of lithium hydroxide is LiOH. Using the periodic table, we can find the atomic masses of lithium (Li), oxygen (O), and hydrogen (H):
- Li: 6.941 g/mol
- O: 15.999 g/mol
- H: 1.008 g/mol
The molar mass of LiOH is calculated as follows:
Molar mass of LiOH = (1 x 6.941 g/mol) + (1 x 15.999 g/mol) + (1 x 1.008 g/mol) = 23.95 g/mol
Converting Grams to Moles, Determine the mass of lithium hydroxide produced when 0.38 grams
Once we have the molar mass, we can convert the given mass of lithium hydroxide (0.38 grams) into moles using the following formula:
Moles = Mass / Molar mass
Substituting the given values:
Moles of LiOH = 0.38 g / 23.95 g/mol = 0.0159 mol
Stoichiometry
Stoichiometry is the study of the quantitative relationships between reactants and products in a chemical reaction. In this case, we need to consider the balanced chemical equation for the production of lithium hydroxide:
2 Li + 2 H2O → 2 LiOH + H2
According to this equation, 2 moles of lithium (Li) react with 2 moles of water (H2O) to produce 2 moles of lithium hydroxide (LiOH). Therefore, the mole ratio between LiOH and Li is 1:1.
Calculating Mass of Lithium Hydroxide Produced
Since we have 0.0159 moles of LiOH, we can calculate the mass of lithium hydroxide produced using the following formula:
Mass = Moles x Molar mass
Substituting the values:
Mass of LiOH = 0.0159 mol x 23.95 g/mol = 0.381 g
Example Calculations
To illustrate the calculations, let’s consider the given mass of 0.38 grams of lithium hydroxide:
- Molar mass of LiOH: 23.95 g/mol
- Moles of LiOH: 0.38 g / 23.95 g/mol = 0.0159 mol
- Mass of LiOH produced: 0.0159 mol x 23.95 g/mol = 0.381 g
Therefore, when 0.38 grams of lithium hydroxide is subjected to the given chemical reaction, approximately 0.381 grams of lithium hydroxide is produced.
FAQs: Determine The Mass Of Lithium Hydroxide Produced When 0.38 Grams
What is the significance of molar mass in this determination?
Molar mass plays a crucial role as it establishes the relationship between the mass and the number of moles of a substance, allowing us to convert between these units and accurately calculate the mass of the product.
How does stoichiometry contribute to this process?
Stoichiometry provides the balanced chemical equation, which reveals the mole ratios between the reactants and products. This information enables us to determine the exact amount of lithium hydroxide produced from the given mass of the starting material.
